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There are ten cards numbered from 1 to 10. Take out three cards from them.

i) the probability that the product of the numbers of the three cards is an odd number is
ii) the probability that the sum of the numbers of the three cards is an even number is

There are ten cards numbered from 1 to 10 Take out three cards from them i the probability that the product of the numbers of the three cards is an odd number i class=

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jcherry99

Answer:

Step-by-step explanation:

Part A

There are 5 odd numbers from 1 to 10. All three of them must be odd when drawn. I have to assume that there is no replacements.

Probability (odd) = (5 *  4 * 3) / (10 * 9 * 8) = 60 / 720

Probability (odd) = 0.083333

Part B

This is a little harder because 1 even number will turn everything even. So the way to handle this is to assume that there is (1 - probability(odd)) *720  that you have even

So the chances of an even result is 1 - odd/ total or

(1 - 1/12) * 720 =   660/720 = 0.917

Answer

Odd: 0.0833

Even: 0.917

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