Respuesta :

Let f(x) = y

y = log3(x+1) - 1

Plug x in y and y in x

x = log3(y+1) - 1

x + 1 = log3(y+1)

3^(x+1) - 1 = y

[tex]y = 3^{x+1}[/tex] - 1

This is the inverse function.

Hope it helps! xxxx

valerieulbrich

Answer:

y = [tex]3^{(x+1)}[/tex] -1

Step-by-step explanation:

x = [tex]log_{3}[/tex](y + 1) - 1

x + 1 = log₃(y + 1)

[tex]3^{(x+1)}[/tex] = y + 1

[tex]3^{(x+1)}[/tex] -1 = y

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