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03-07-2019
Physics

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Consider a generator that rotates its 200 turn, 0.18 m diameter coil at 3250 rpm in a 0.65 T field. Calculate the peak voltage of the generator.

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Vespertilio Vespertilio

10-07-2019

Answer:

1124.8 Volt

Explanation:

N = 200, Diameter = 0.18 m, Radius, r = 0.09 m, f = 3250 rpm = 54.17 rps

B = 0.65 T

the peak value of induced emf is given by

e0 = N x B x A x ω

e0 = 200 x 0.65 x 3.14 x 0.09 x 0.09 x 2 x 3.14 x 54.17

e0 = 1124.8 Volt

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